Y=0.02x^2-x

Solution for Y=0.02x^2-x equation:

=0.02Y^2-Y

We move all terms to the left:

-(0.02Y^2-Y)=0

We get rid of parentheses

-0.02Y^2+Y=0

a = -0.02; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-0.02)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-0.02}=\frac{-2}{-0.04}
=+50
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-0.02}=\frac{0}{-0.04}
=0
$